Question 18186
Let n be the first integer.
{{{n+(n+2)+(n+4)+(n+6)=184}}}
simplify
{{{4n+12=184}}}
{{{4n=172}}}
{{{n=43}}}
if the first one is 43, then the intergers are 43,45,47,and 49
Check.
add them up 
43+45+47+49
88+96=
184