Question 123006

Let's evaluate f(-2)


{{{f(x)=-x^3-2x^2+3x-9}}} Start with the given function



{{{f(-2)=-(-2)^3-2(-2)^2+3(-2)-9}}} Plug in {{{x=-2}}}



{{{f(-2)=-1*-8-2*-2^2+3*-2-9}}} Raise -2 to the 3rd power to get -8



{{{f(-2)=8-2*-2^2+3*-2-9}}} Negate -8 to get 8



{{{f(-2)=8-2*4+3*-2-9}}} Raise -2 to the 2nd power to get 4



{{{f(-2)=8-8+3*-2-9}}} Multiply 2 and 4 to get 8



{{{f(-2)=0+3*-2-9}}} Subtract 8 from 8 to get 0



{{{f(-2)=0+-6-9}}} Multiply 3 and -2 to get -6



{{{f(-2)=-6-9}}} Add 0 and -6 to get -6



{{{f(-2)=-15}}} Subtract 9 from -6 to get -15





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Let's evaluate f(0)



{{{f(x)=-x^3-2x^2+3x-9}}} Start with the given function



{{{f(0)=-1(0)^3-2(0)^2+3(0)-9}}} Plug in {{{x=0}}}



{{{f(0)=0-2*0^2+3*0-9}}} Raise 0 to the 3rd power to get 0




{{{f(0)=0-2*0+3*0-9}}} Raise 0 to the 2nd power to get 0



{{{f(0)=0-0+3*0-9}}} Multiply 2 and 0 to get 0



{{{f(0)=0+3*0-9}}} Subtract 0 from 0 to get 0



{{{f(0)=0+0-9}}} Multiply 3 and 0 to get 0



{{{f(0)=0-9}}} Add 0 and 0 to get 0



{{{f(0)=-9}}} Subtract 9 from 0 to get -9





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Let's evaluate f(1)



{{{f(x)=-x^3-2x^2+3x-9}}} Start with the given function



{{{f(1)=-(1)^3-2(1)^2+3(1)-9}}} Plug in {{{x=1}}}



{{{f(1)=-1*1-2*1^2+3*1-9}}} Raise 1 to the 3rd power to get 1



{{{f(1)=-1-2*1^2+3*1-9}}} Negate 1 to get -1



{{{f(1)=-1-2*1+3*1-9}}} Raise 1 to the 2nd power to get 1



{{{f(1)=-1-2+3*1-9}}} Multiply 2 and 1 to get 2



{{{f(1)=-3+3*1-9}}} Subtract 2 from -1 to get -3



{{{f(1)=-3+3-9}}} Multiply 3 and 1 to get 3



{{{f(1)=0-9}}} Add -3 and 3 to get 0



{{{f(1)=-9}}} Subtract 9 from 0 to get -9