<PRE><B>Question 122844</B>
The position of an object moving in a straight line is given by s=2tsquared - 3t, where s is in meters and t is the time in secoonds the object has been in motion. How long (to the nearest tenth) will it take the object to move 19 meters?
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s(t) = 2t^2-3t
19 = 2t^2-3t
2t^2-3t-19=0
t = [3 +- sqrt(9-4*2*-19)]/4
t = [3 +- sqrt(161)]/4
t = [3 +- 12.6886]/4
Positive answer:
t = [3+12.6886]/4
t = 3.9221 seconds
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Cheers,
Stan H.


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