Question 122723
Given the equation:
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{{{V = pi*r^2*h}}}
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Solve for h.
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On the right side recognize that {{{h}}} is multiplied by {{{pi*r^2}}}. If you divided the
right side by this multiplier, the right side would become:
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{{{((pi*r^2)*h)/(pi*r^2)}}}
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But if you divide the right side of an equation by some quantity, you must also divide the
left side by the same quantity to keep the equation in balance. So to keep the given equation
in balance, when we divide the right side by {{{pi*r^2}}} we also divide the left side 
by the same quantity and the equation becomes:
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{{{V/(pi*r^2)= ((pi*r^2)*h)/(pi*r^2)}}}
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On the right side the {{{pi}}} in the numerator cancels with the {{{pi}}} in the denominator,
and the {{{r^2}}} in the numerator cancels with the {{{r^2}}} in the denominator. 
As a result of these cancellations, all you are left with on the right side is {{{h}}}. Therefore,
the equation is reduced to:
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{{{V/(pi*r^2) = h}}}
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And if you transpose the equation (switch sides) you are left with:
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{{{h = V/(pi*r^2)}}}
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and this is what the problem asked you to do ... to solve for h in terms of the other variables
given in the problem.
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Hope this helps you to understand the problem and how you can solve it.
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