Question 122760
{{{y = x^2 - 3x - 10}}}
The x-intercept occurs where {{{y=0}}}
{{{x^2 - 3x - 10 = 0}}}
{{{(x - 5)(x + 2)}}} 
{{{x = 5}}}
{{{x = -2}}}
These are the x-intercepts- either one makes {{{y=0}}}
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{{{y = -(x)^2 - 6x + 2}}}
When the equation is in the form {{{y = ax^2 + bx + c}}},
the axis of symmetry is at the line {{{x = (-b)/(2a)}}}
In this case, 
{{{a = -1}}}
{{{b = -6}}}
{{{x = (-(-6)) / (2*(-1))}}}
{{{x = -3}}} axis of symmetry
I'll check this by plotting
{{{ graph( 600, 600, -9, 5, -10, 12, -(x)^2 - 6x + 2) }}}