Question 122760
Find the x-intercept of y = x squared - 3x - 10 
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Let y = 0 and solve for "x":
x^2-3x-10 = 0
(x-5)(x+2)=0
x = 5 and x=-2 are the x-intercepts.
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Find the axis of symmetry of y = -x squared - 6x + 2
The axis occurs at x = -b/2a = 6/(2(-1)) = 3
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Cheers,
Stan H.