Question 122741
Find the x-intercept:
{{{y = x^2+x-6}}} The x-intercepts (there will be two of them) occur at y = 0, so...
{{{0 = x^2+x-6}}} Solve by factoring:
{{{0 = (x+3)(x-2)}}} Apply the zero product principle:
{{{x+3 = 0}}} or {{{x-2 = 0}}} so then...
If {{{x+3 = 0}}} then {{{x = -3}}} or...
If {{{x-2 = 0}}} then {{{x = 2}}} 
The x-intercepts are:
{{{x = -3}}} and {{{x = 2}}}
Check the graph:
{{{graph(600,400,-5,5,-8,5,x^2+x-6)}}}