Question 122683
Does your question look like this: {{{(3)/(4)=1-(3x-2)/(x+1)}}}??




{{{(3)/(4)=1-(3x-2)/(x+1)}}} Start with the given equation



{{{(4(x+1))((3)/(cross(4)))=(4(x+1))(1-(3x-2)/(cross(x+1)))}}} Multiply both sides by the LCD {{{4(x+1)}}}. Doing this will eliminate every fraction.



{{{(x+1)(3)=4(x+1)-4(3x-2)}}} Distribute and multiply. Notice every denominator has been canceled out.




{{{3(x+1)=4(x+1)-4(3x-2)}}} Rearrange the left side




{{{3x+3=4x+4-12x+8}}} Distribute




{{{3x+3=-8x+12}}} Combine like terms on the right side



{{{3x=-8x+12-3}}}Subtract 3 from both sides



{{{3x+8x=12-3}}} Add 8x to both sides



{{{11x=12-3}}} Combine like terms on the left side



{{{11x=9}}} Combine like terms on the right side



{{{x=(9)/(11)}}} Divide both sides by 11 to isolate x




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Answer:

So our answer is {{{x=9/11}}}  (which is approximately {{{x=0.818181818181818}}} in decimal form)