Question 122660
Let L=length, w=width

Since the length is "3 in. more than twice its width", this means: {{{L=2w+3}}}



{{{P=2w+2L}}} Start with the perimeter formula



{{{36=2w+2(2w+3)}}} Plug in the given perimeter {{{P=36}}} and {{{L=2w+3}}}



{{{36=2w+4w+6}}} Distribute



{{{36=6w+6}}} Combine like terms on the right side



{{{0=6w+6-36}}}Subtract 36 from both sides



{{{-6w=6-36}}} Subtract 6w from both sides



{{{-6w=-30}}} Combine like terms on the right side



{{{w=(-30)/(-6)}}} Divide both sides by -6 to isolate w




{{{w=5}}} Divide


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Answer:

So our answer is {{{w=5}}} 




So the width is 5 inches