Question 122661
If {{{k<0}}} then the solution will not be a real number. To see why, let's solve for x:



{{{x^2=k}}} Start with the given equation



{{{x=0+-sqrt(k)}}} Take the square root of both sides



So if {{{k<0}}}, then we won't have a real answer (remember you cannot take the square root of a negative number). So the answer will be an complex number.