Question 122491
{{{2y^2-3y-6=0}}}
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} Use the quadratic equation. 
{{{y = (-(-3) +- sqrt( (-3)^2-4*2*(-6) ))/(2*2) }}}
{{{y = (3 +- sqrt( 9+48 ))/(4) }}}
{{{y = (3 +- sqrt( 57 ))/(4) }}} Two real solutions. 
Exactly the roots are, 
{{{y[1] = (3 + sqrt( 57 ))/(4) }}}
{{{y[2] = (3 - sqrt( 57 ))/(4) }}}
or approximately,
{{{y[1] = 2.637}}}
{{{y[2] = -1.137}}}
{{{ graph( 300, 300, -5, 5, -5, 5, 2x^2-3x-6) }}}