Question 122450
"the image of an object is 4cm closer to the lens than the object itself"
__ y=x-4


1/4.8=(1/x)+(1/(x-4))


multiplying by 24x(x-4) __ 5x^2-20x=24x-96+24x __ 5x^2-68x+96=0


factoring __ (5x-8)(x-12)=0



the two solutions represent the "real" image and the "virtual" image