Question 122527


let numbers be {{{x}}} and {{{y}}}, and let sat {{{x>y}}}

if one number is {{{eleven}}} more than {{{twice}}} another, then you have:

{{{x = 2y + 11}}}......................(1)

 if their {{{sum}}} is {{{decreased}}} by ten, the result is {{{13}}}. means:

{{{(x+y)-10 = 13}}}...or

{{{x + y = 23}}}......................(2)

now solve the system to find the numbers.:

{{{x = 2y + 11}}}......................(1)...this one is solved for {{{x}}}; so plug {{{x}}} into (2)

{{{2y + 11 + y = 23}}}......................(2)

 {{{2y + 11 + y = 23}}}.............

 {{{3y  = 23 -11 }}}.............

 {{{3y  = 12}}}.............

 {{{y  = 4}}}.............

{{{x = 2y + 11}}}......................(1)...plug in {{{y}}}

{{{x = 2*4 + 11}}}..............

{{{x = 19}}}..............