Question 122453
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{{{4x^2-8x+1=0}}}

a = 4
b = -8
c = 1

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-(-8) +- sqrt( (-8)^2-4*4*1 ))/(2*4) }}} 
{{{x = (8+-sqrt(64-16))/8 }}} 
{{{x = (8+-sqrt(48))/8}}}
{{{x = (8+4sqrt(3))/8}}} or {{{x = (8-4sqrt(3))/8}}}

Your answer was technically correct, but you should have reduced it to lowest terms:

{{{x=(2+-sqrt(3))/2}}}


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