Question 122371
there is no "a" term on the right-hand side of the equation
__ the only way this can happen is if #=0 (a^0=1)
__ if # had any other value, there would be an "a" term on both sides


so you have 1/3b^&=b^3/3


multiplying by 3 clears the fractions __ b^&=b^3


so &=3