Question 122147
Question:

The length of a rectangle is 2 in. more than twice its width.  If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle

Answer:

The perimeter of the rectangle is given by the formula,



P = 2(length +width)


Assume that, width = x inches



Then its length = 2x+2 inches( because it is given that more than  twice its width)




So P = 2( 2x+2 +x) that is substitute the values of length and width.


But P = 34 inches, given


==> 34 = 2( 3x + 2)



==> 34 = 6x + 4



Subtract 4 from both sides




==> 34- 4 = 6x + 4 -4





==> 30 = 6x  


Divide by 6 on both sides..



==> {{{ 30/6 = 6x/6}}}



==> 5 = x


That is width = 5 inches



So length = 2(5) + 2



==> length = 12 inches.


Hope ypou found the explanation useful.


Regards.

Praseena.