Question 122174
{{{b^2-2bc+c^2}}} Start with the given expression



{{{(3)^2-2(3)(-2)+(-2)^2}}} Plug in {{{b=3}}} and {{{c=-2}}}



{{{9-2(3)(-2)+4}}} Square 3 to get 9. Square -2 to get 4. 



{{{9+12+4}}} Multiply -2, 3 and -2 to get 12 



{{{25}}} Add 



So {{{b^2-2bc+c^2=25}}} when {{{b=3}}} and {{{c=-2}}}