Question 122074
Not quite right...you are OK up to this point:
cube_root_of x=8
But to find x, you need to cube both side of the equation:
{{{x=8^3}}}
{{{highlight(x=512)}}}
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You were confusing how to incorporate that 1/3 term... 
The cube_root_of x is also written as:
{{{x^(1/3)}}}
Don't confuse that with what you did
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Good Luck,
tutor_paul@yahoo.com