Question 121918
{{{(2x/(x^3-5x^2))-(2/(x^2+5x))}}}
I have come up with 20/x(x-5)(x+5).  Is that answer right?
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2x/(x^3-5x^2) - 2/(x^2+5x)

= 2x/[x^2(x-5)] - 2/[x(x+5)]

lcd = x^2(x^2-25)

= 2x(x+5)/lcd - 2x(x-5)/lcd

= [2x^2+10x-2x^2+10x]/lcd

= 20x/[x^2(x^2-25)]

= 20/[x(x^2-25)]

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You are correct.
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Cheers,
Stan H.