Question 121908
(7c)^4(7c)^7
= (7c) ^ (4+7)            When we are multiplying we add the exponents
=  (7c)^11   ----> Answer


(x^4-5x^2+6)/(x^2-3)

=(x^2-3)(x^2-2) / (x^2-3)    

Cancelling out (x^2 - 3) from Numerator and Denominator

= (x^2-2) ----> Answer



factor by mult

x^9+8x^8

Only x^8 is common so we get

x^8(x+8)  ----> Answer

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