Question 121906
{{{n^2 + 48 = 16 + 12n}}}
subtract {{{16 + 12n}}} from both sides
{{{n^2 - 12n + 32 = 0}}}
I notice that {{{-4*-8 = 32}}} and {{{-4 -8 = -12}}},
so my factors are:
{{{(n - 4)(n - 8)}}}
This is true if either {{{n = 4}}} or {{{n = 8}}}