Question 121752
{{{P=-x^2+56x-300}}} Start with the given profit equation 




{{{0=-x^2+56x-300}}} Plug in P=0 




{{{0=-(x-6)(x-50)}}} Factor the right side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-6=0}}} or {{{x-50=0}}}


{{{x=6}}} or {{{x=50}}}      Now solve for x in each case






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Answer:



So when either 6 tiles or 50 tiles are sold, the profit is $0