Question 18607
cosider rhombus ABCD..we have AB=BC=CD=DA=x say..diagonals are AC and BD.consider triangle ABC..as per the property of triangles sum of any 2 sides is more than the third side..so
AB+BC>AC..or  2x>AC
similarly in triangle BCD,we have BC+CD>BD...or..2x>BD
adding these 2 eqns...we have 2x+2x>AC+BD..or..4x>AC+BD
so perimeter is more than sum of diagonals..or sum of diagonals is less than perimeter....TRUE