Question 121697
It looks like you may have forgotten part of these equations when you wrote them.


In their current state, {{{2x-2>5}}} needs to be solved for x, thus:


{{{2x-2>5}}}
{{{2x>5+2}}}
{{{2x>7}}}
{{{x>7/2}}}


On the number line, this would graph by putting a circle at {{{7/2}}} to indicate that {{{7/2}}} itself is NOT an element of the solution set, and then making a heavy line to the right of your circle to indicate that everything larger than {{{7/2}}} IS an element of the solution set.


The second problem comes out to {{{x>=19/7}}}.  Since you have "or equal," you would make a solid dot at {{{19/7}}} because {{{19/7}}} IS included in the solution set.


If you are trying to graph these on a coordinate plane, you would either have a dashed vertical line at {{{7/2}}} with everything to the right shaded for the first problem, or a solid vertical line at {{{19/7}}} with everything to the right shaded for the second problem.


On the other hand, if you really meant to write


{{{2x-2y>5}}} and
{{{7x-3y>=16}}}


That is another story altogether.


In this case, solve the inequality for y.  Then graph the analogous equation. 


{{{2x-2y>5}}}


{{{-2y>-2x+5}}}


Divide by -2 (remember, since you are dividing by a negative, reverse the sense of the inequality)
{{{y<x-(5/2)}}}


The analogous equation would be {{{y=x-(5/2)}}}, a line with a slope of 1 and a y-intercept of {{{-(5/2)}}}.  Go ahead and plot this line on the graph, but you need to make it a dashed line because the original inequality did not include equality.


{{{graph(400,400,-5,5,-5,5,x-(5/2))}}}


The last thing is to determine which half-plane to shade.  Select a convenient point that is NOT on the line.  Let's pick (1,1) which is above and to the left of the line, and substitute these coordinate values into the original equation.


{{{2(1)-2(1)>5}}}
{{{0>5}}}.  This statement is clearly false, therefore the selected point is on the wrong side of the line -- so shade in the other side.  Your final result should be a dashed line where the line on the graph above is, with everything below and to the right of the line shaded.


The dashed line means that points ON the line are NOT included in the solution set.  For example, the point (1,-3/2) is on the line but {{{2(1)-2(-3/2)}}} equals 5, but is not greater than 5.


The other equation will work out pretty much the same way, except that you will have a solid line because the inequality includes equals.


Write back if you are still having trouble.


John