Question 121640
13^2=a^2+b^2 where 34/2=17 or  a+b=17 or a=17-b
13^2=(17-b)^2+b^2
169=289-34b+b^2+b^2
2b^2-34b+289-169=0
2b^2-34b+120=0
2(b^2-17b+60)=0
2(b-12)(b-5)=0
b-12=0
b=12 one side
b-5=0
b=5 the other side.
proof
2*12+2*5=34
24+10=34
34=34
12^2+5^2=13^2
144+25=169
1169=169