Question 121525
The distance between two points is given by,
{{{D^2=(x[1]-x[2])^2+(y[1]-y[2])^2)}}}
{{{13=(7-3)^2+(y-3)^2)}}}
{{{13=16+(y-3)^2)}}}
{{{(y-3)^2=-3)}}}
You cannot square a number and get a negative value. 
Therefore, there is no solution for y such that the distance is {{{sqrt(13)}}}.