Question 121261


{{{x + y = 5}}}………………………..(1)

{{{x-y = 1}}}………………………..(2)


Solve this system:


{{{x + y = 5}}}………………………..(1)… =>…{{{x = -y + 5}}}

{{{x-y = 1}}}………………………..(2)…substitute {{{x}}} and find {{{y}}}

{{{-y + 5 -y = 1}}}………………………..(2)

{{{-2y = 1 - 5}}}…

{{{-2y =  - 4}}}………divide both sides by {{{-2}}}


{{{y =  2}}}………

=>…{{{x = -y + 5}}}

{{{x = -2 + 5}}}

{{{x = 3}}}

So, the point is ({{{3}}},{{{2}}}) and it is intersection of these two lines


here is the graph:


*[invoke solve_by_graphing 1, 1, 5, 1, -1, 1]