Question 121236
<pre><font size = 4><b>
Graph the following equations; calculate the slope, 
x-intercept, and y-intercept, and label the intercepts 
on the graph: 

{{{4y = 7}}}

We write that in standard form

{{{y = mx + b}}}

where m is the slope and (0,b) is the y-intercept:

So first to get the y we multiply both sides by {{{1/4}}}

{{{4y = 7}}}

{{{(1/4)4y = (1/4)7}}}

{{{y = 7/4}}}

Now that is not in the form {{{y=mx+b}}}
but we can easily make it in that form by adding {{{0x}}}
to the right side in front of the {{{7/4}}}:

{{{y = 0x + 7/4}}}

Now we compare this to 

{{{y = mx + b}}}

and find {{{m=0}}} and {{{b=7/4}}}, so the slope is 0
and the y-intercept is (0,{{{7/4}}}).

To plot the y-intercept, we first convert {{{7/4}}}
to the mixed fraction {{{1}}}{{{3/4}}} and plot a
point on the y-axis, {{{3/4}}}ths of the way between
1 and 2 on the y-axis:

{{{drawing(300,300,-5,5,-5,5,graph(300,300,-5,5,-5,5),
locate(-.12,2.05,o) )}}}

Now since the slope is 0, that makes it easy. Lines
with slope 0 are always horizontal.  Therefore we
draw a horizontal line through that point:

{{{drawing(300,300,-5,5,-5,5,graph(300,300,-5,5,-5,5,7/4),
locate(-.12,2.05,o) )}}}

So the slope is 0, the y-intercept is (0,{{{7/4}}}), and
there can be no x-intercept because the line is horizontal
and therefore parallel to the x-axis and therefore can
never intersect it.

Edwin</pre>