Question 121208
Solve for w:
{{{w^3+5W^2-w = 5}}} First, subtract 5 from both sides.
{{{w^3+5w^2-w-5 = 0}}} Then factor the left side.
{{{(w^2-1)(w+5) = 0}}} Apply the zero product principle.
{{{w^2-1 = 0}}} or {{{w+5 = 0}}}
If {{{w^2-1 = 0}}} then {{{w^2 = 1}}} so {{{w = 1}}} or {{{w = -1}}}
If {{{w+5 = 0}}} then {{{w = -5}}}
The solutions are:
{{{w = 1}}}
{{{w = -1}}}
{{{w = -5}}}