Question 121032
{{{4x^2+8x-7=0}}}
{{{x^2+2x-7/4=0}}}Divide both sides by 4.

{{{x^2+2x-7/4+1=1}}}Add 1 to both sides of the equation

{{{(x^2+2x+1)-7/4=1}}}

{{{(x+1)^2-7/4=1}}} Complete the square.

{{{(x+1)^2=1+7/4}}}Add 7/4 both sides.

{{{(x+1)^2=4/4+7/4}}}Same denominator on the right hand side.

{{{(x+1)^2=11/4}}}

1.{{{ x+1=sqrt(11)/2}}}First solution

{{{x=sqrt(11)/2-1}}}

2. {{{x+1=-sqrt(11)/2}}}Second solution

{{{x=-sqrt(11)/2-1}}}