Question 121044
Let's say your numbers are m and n.


The first thing we know is that {{{n + m = 65}}}.


Let's assume that {{{n>m}}}, so {{{n/m=3+5/m}}}


Multiplying by m:


{{{n=3m + 5}}}, or
{{{n-3m=5}}}


Now we have two standard form equations in two variables, so


{{{n + m = 65}}}
{{{n-3m=5}}}


Multiply the second equation by -1:


{{{n + m = 65}}}
{{{-n+3m=-5}}}


Now add the equations, term by term:


{{{0n+4m=60}}}


Divide by 4:


{{{m=15}}}


Now that we know the value of m, we can calculate n by {{{n=65-15=50}}}


Note that {{{n>m}}} is true.


Check:

50 divided by 15 is 3 with a remainder of 5.  Checks.