Question 120912
4x^2+6xy+9y^2
using the quadratic equation:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get:
x=(-6+-sqrt[6^2-4*4*9])/2*4
x=(-6+-sqrt[36-144])/8
x=(-6+-sqrt-108])/8
x=(-6+-10.39i)/8
x=(-6+10.39i)/8
x=-6/8+1.299i
x=-.75+-1.299i answers.