Question 120944
x^2-2x+8=0
x = [2 +- sqrt(4-4*8)]/2
x = [2 +- sqrt(-28)]/2
x = [2 +- 2isqrt(7)]/2
x = [1 +- isqrt7]
x = 1+isqrt7 or x = 1-isqrt7
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Cheers,
Stan H.