Question 120927
2x/3=2/(3x-1) now cross multiply.
2x(3x-1)=3*2
6x^2-2x-6=0
2(3x^2-x-3)=0 USING THE QUADRATIC EQUATION.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}  WE GET.
X=(1+-SQRT[-1^2-4*3*-3])/2*3
X=(1+-SQRT1+36])/6
X=(1+-SQRT370/6
X=(1+-6.08)/6
X=(1+6.08)/6
X=7.08/6
X=1.18 ANSWER.
X=1-6.08)/6
X=-5.08/6
X=-.84 ANSWER.