Question 120802

{{{((-18a^6)/(x^2))*((4x^3)/(9a^2))}}} Start with the given expression



{{{((-18a^6)*(4x^3))/((x^2)*(9a^2))}}} Combine the fractions



{{{(-72a^6x^3)/(9a^2x^2)}}} Combine the fractions by multiplying. Don't forget to multiply the coefficients.



{{{-8a^4x^1}}} Divide the expression by subtracting the exponents. Remember {{{x^5/x^3=x^(5-3)=x^2}}}. Don't forget to divide the coefficients.




So {{{((-18a^6)/(x^2))*((4x^3)/(9a^2))}}} simplifies to {{{-8a^4x^1}}}


In other words, {{{((-18a^6)/(x^2))*((4x^3)/(9a^2))=-8a^4x^1}}}