Question 2135
{{{8x^3 - 27}}} equals {{{(2x)^3 - 3^3}}}
<br>
Remember the difference of 2 cubes?  It states {{{a^3 - b^3}}} = {{{(a - b)(a^2 + ab + b^2)}}}
<br>
In this equation the a=2x and the b=3.  So we have:
<br>
{{{(2x - 3)((2x)^2 + (2)(3) + 3^2)}}}
<br>
Which simplifies to be...
<b>{{{(2x - 3)(4x^2 + 6x + 9)}}}</b>