Question 120785
In excercises 34-36,use the spinner to find the probability. The spinner is divided into equal parts.The spinner numbers are 1-12 in a circle

35. What are the odds in favor of stopping on a multiple of 3?

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The multiples of 3 are 3,6,9,12
There are four multiples of three.
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Probability(landing on a multiple of 3) = 4/12 = 1/3
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Odds "in favor of" an event = P(event happens)/P(event does not happen)
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Your Problem:
Odds in favor of stopping on multiple of 3) = (1/3)/(2/3) = 1/2 = 1:2
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Cheers,
Stan H.