Question 120762
Start by trying to find all the factors of 486. 
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Since 486 is an even number, obviously 2 is a factor. So you can write that:
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{{{486 = 2*243}}}
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Now try to factor 243. A little thought will convince you that 3 is a factor of 243. That
being the case, you can now say that:
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{{{486 = 2*3*81}}}
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Note that 81 can be factored into 9 times 9. So you now have:
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{{{486 = 2*3*9*9}}}
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But each of the 9's can be factored to 3*3 and this further reduces the problem to:
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{{{486 = 2*3*3*3*3*3}}}
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and since there are 5 factors of 3, you can further say:
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{{{486 = 2*3^5}}}
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The problem required you to find the 5th root of 486. You can substitute {{{2*3^5}}} for
486 and you have:
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{{{root(5,486)= root(5,2*3^5) = root(5,3^5)*root(5,2)}}}
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But the 5th root of {{{3^5}}} is 3. Substituting this simplification reduces the problem to:
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{{{root(5,486) = 3*root(5,2)}}}
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Hope this helps you to understand the problem.
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