Question 18447
{{{ ((2*x*y^2*z^4)/(3*x*y*z^-1))^-2  }}}

x cancels off from the numerator and denominator

{{{ ((2*y^2*z^4)/(3*y*z^-1))^-2  }}}

Raise everything to the power (-2)

{{{ ((2^-2*y^(2*-2)*z^(4*-2))/(3^-2*y^-2*z^(-1*-2)))  }}}

{{{ ((2^-2*y^-4*z^-8)/(3^-2*y^-2*z^2))  }}}

Negative Powers can reciprocate the variable
ie x^-2 becomes 1/x^2

{{{ ((3^2*y^2)/(2^2*y^4*z^(2+8)))  }}}

{{{ (9*y^2)/( 4*y^4*z^(2+8) )  }}}

{{{ (9*y^2)/( 4*y^4*z^10 )  }}}

{{{ 9/( 4*y^(4-2)*z^10 )  }}}

{{{ 9/( 4*y^2*z^10 )  }}}
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Hope this helps,
Prabhat