Question 120700


{{{(9x+9)(3x+3)}}} Start with the given expression



Now let's FOIL the expression




Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(9x)+9)(highlight(3x)+3)}}} Multiply the First terms:{{{(9x)*(3x)=27x^2}}}



{{{(highlight(9x)+9)(3x+highlight(3))}}} Multiply the Outer terms:{{{(9x)*(3)=27x}}}



{{{(9x+highlight(9))(highlight(3x)+3)}}} Multiply the Inner terms:{{{(9)*(3x)=27x}}}



{{{(9x+highlight(9))(3x+highlight(3))}}} Multiply the Last terms:{{{(9)*(3)=27}}}



{{{27x^2+27x+27x+27}}} Now collect every term to make a single expression




{{{27x^2+54x+27}}} Now combine like terms



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Answer:

So {{{(9x+9)(3x+3)}}} foils and simplifies to  {{{27x^2+54x+27}}}


In other words, {{{(9x+9)(3x+3)=27x^2+54x+27}}}