Question 120649
#5



First convert the standard equation {{{2x-3y=6}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 2, -3, 6, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(2/3)x-2}}} which goes through (0,2)


*[invoke equation_parallel_or_perpendicular "perpendicular", "2/3", "-2", 0,2]