Question 120550
Start with the given distance formula

{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} where *[Tex \Large \left(x_{1}, y_{1}\right)] is the first point *[Tex \Large \left(5,6\right)] and *[Tex \Large \left(x_{2}, y_{2}\right)] is the second point *[Tex \Large \left(9,0\right)]


{{{d=sqrt((5-9)^2+(6-0)^2)}}} Plug in {{{x[1]=5}}}, {{{x[2]=9}}}, {{{y[1]=6}}}, {{{y[2]=0}}}


{{{d=sqrt((-4)^2+(6)^2)}}} Evaluate {{{5-9}}} to get -4. Evaluate {{{6-0}}} to get 6. 


{{{d=sqrt(16+36)}}} Square each value


{{{d=sqrt(52)}}} Add


{{{d=2*sqrt(13)}}} Simplify the square root  (note: If you need help with simplifying the square root, check out this <a href=http://www.algebra.com/algebra/homework/Radicals/simplifying-square-roots.solver> solver</a>)



So the distance approximates to


{{{d=7.21110255092798}}}


which rounds to

7.21


So the distance between (5,6) and (9,0) is approximately 7.21 units