Question 120438
{{{(sqrt(-7) sqrt(-49)) / sqrt(-63)}}} Start with the given expression



{{{(sqrt(7)*i 7*i) / (3*i*sqrt(7))}}} Simplify the square roots




{{{(cross(sqrt(7))*cross(i) 7*i) / (3*cross(i)*cross(sqrt(7)))}}} Cancel like terms


{{{7i/3}}} Simplify. So the expression is now in {{{a+bi}}} form where {{{a=0}}} and {{{b=7/3}}}. Note: the expression really looks like {{{0+(7/3)i}}}