Question 120316
The process is to invert and multiply:


Divide {{{p/q}}} by {{{r/s}}}


{{{(p/q)/(r/s)=(p/q)(s/r)=(ps)/(qr)}}}, and then reduce {{{ps/qr}}} to lowest terms


Notice that {{{r/s}}} became {{{s/r}}} in the intermediate step.


Divide {{{4/3}}} by {{{2/3}}}


{{{(4/3)/(2/3)=(4/3)(3/2)=(12)/(6)}}}, and then reduce {{{12/6}}} to lowest terms:  {{{12/6=(2*6)/6=(2*cross(6))/(1*cross(6))=2}}}


Hope that helps,
John


P.S. In the future, please stop using ALL CAPS to type your question.