Question 120253

the equation in standard form: {{{ax + by = c}}}

so, you will have:

{{{ -(1/2)(y+1) = (x-2)^2 }}}…….move {{{(x-2)^2}}} to the left


{{{ -(x-2)^2 - (1/2)(y+1) = 0 }}}……. the equation in standard form