Question 120217
Find {{{f(x+3)}}} for the function {{{f(x)=x^2-4}}}


Replace {{{x}}} in {{{f(x)}}} every place {{{x}}} occurs.


{{{f(x+3)=(x+3)^2-4}}}


Now expand the binomial and simplify:


{{{f(x+3)=x^2+6x+9-4=x^2+6x+5}}}