Question 120203
Actually, this looks like a horror, but it isn't really that bad.


{{{x^2-(6/5)x+9/25=0}}}


Note that {{{9/25}}} = {{{(3/5)^2}}}, and {{{-(3/5)+(-(3/5))=-(6/5)}}}


So, this factors to:


{{{(x-3/5)(x-3/5)=0}}}


{{{(x-3/5)(x-3/5)=0}}} if and only if {{{x=3/5}}}, so the two roots of this equation are {{{3/5}}} and {{{3/5}}}.


Hope this helps,
John