Question 120191
{{{18x^2-12x^3=0}}} Start with the given equation


{{{6x^2(3-2x)=0}}} Factor out the GCF {{{6x^2}}}




Now set each factor equal to zero:


{{{6x^2=0}}} or  {{{3-2x=0}}} 


Now solve for x for each factor:


{{{x=0}}} or  {{{x=3/2}}} note: since the left term is squared, this means the zero occurs twice.


So the zeros of {{{18x^2-12x^3}}} are:


 {{{x=0}}} (with a multiplicity of 2) and  {{{x=3/2}}} 




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Is it supposed to read: {{{9x^2-3x=0}}}?


{{{9x^2-3x=0}}} Start with the given equation


{{{3x(3x-1)=0}}} Factor out the GCF {{{3x}}}




Now set each factor equal to zero:


{{{3x=0}}} or  {{{3x-1=0}}} 


Now solve for x for each factor:


{{{x=0}}} or  {{{x=1/3}}} 


So the zeros of {{{9x^2-3x}}} are:



 {{{x=0}}} or  {{{x=1/3}}}