<PRE><B>Question 120078</B>
The path of a falling object is given by the function s=-16t^2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet. 
If a rock is thrown upward with an initial velocity of 32 feet per second from the top of a 40-foot building, write the height (s) equation using this information.
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EQUATION:
h(t)=-16t^2+32t+40
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How high is the rock after 0.5 second?
Find h(0.5) = 52 ft
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After how many seconds will the graph reach maximum height?
Maximum height when t = -b/2a = -32/(-2*16)= 1 second
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What is the maximum height?
Find h(1) = -16+32+40 = 56 ft
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Cheers,
Stan H. 

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