<PRE><B>Question 119926</B>
y= -x^2+6x-1 please help
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a. write the equation for the axis of symmetry.
The axis of symmetry equation: x = {{{(-b)/(2a)}}}
In the above equation a=-1: b=6, so we have:
x = {{{(-6)/(2*-1)}}} = +3
The axis of symmetry is at x=3
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b. use the equation to create a table of values for the quadratic equation finding values of both sides of the axis of symmetry.
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Substitute each value for x in the equation and find y. 
You table should look like this:
 x | y
-------
 -1|-8
  0|-1
 +1|+4
 +2|+7
 +3|+8; axis of symmetry, max value 
 +4|+7
 +5|+4
 +6|-1
:
Note the that x intercepts (where it crosses 0)
between x=0 and x=+1. And x=+5, and x=+6
:
Plot these values, a graph of this: 
{{{ graph( 300, 200, -4, 8, -10, 10, -x^2+6x-1) }}}
:
Did this help you understand this?</PRE>